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20130112221 = 36710037407
BaseRepresentation
bin10010101111110110…
…010010001011011101
31220221220100122122220
4102233312102023131
5312211302042341
613125254055553
71311562062552
oct225766221335
956856318586
1020130112221
11859aa1828a
123a9964a5b9
131b8a63250b
14d8d6b4a29
157cc3bca66
hex4afd922dd

20130112221 has 4 divisors (see below), whose sum is σ = 26840149632. Its totient is φ = 13420074812.

The previous prime is 20130112217. The next prime is 20130112273. The reversal of 20130112221 is 12221103102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20130112221 - 22 = 20130112217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20130112221.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130112021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355018701 + ... + 3355018706.

It is an arithmetic number, because the mean of its divisors is an integer number (6710037408).

Almost surely, 220130112221 is an apocalyptic number.

It is an amenable number.

20130112221 is a deficient number, since it is larger than the sum of its proper divisors (6710037411).

20130112221 is an equidigital number, since it uses as much as digits as its factorization.

20130112221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6710037410.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20130112221 its reverse (12221103102), we get a palindrome (32351215323).

The spelling of 20130112221 in words is "twenty billion, one hundred thirty million, one hundred twelve thousand, two hundred twenty-one".

Divisors: 1 3 6710037407 20130112221