Base | Representation |
---|---|
bin | 11101010010110000111… |
… | …000001111111101011011 |
3 | 21010102221021122121210202 |
4 | 131102300320033331123 |
5 | 230440122112324404 |
6 | 4140433130132415 |
7 | 265302214430432 |
oct | 35226070177533 |
9 | 7112837577722 |
10 | 2013012229979 |
11 | 706793a19863 |
12 | 28617588110b |
13 | 117a9832893a |
14 | 6d604ac0119 |
15 | 3756a54821e |
hex | 1d4b0e0ff5b |
2013012229979 has 2 divisors, whose sum is σ = 2013012229980. Its totient is φ = 2013012229978.
The previous prime is 2013012229973. The next prime is 2013012230017. The reversal of 2013012229979 is 9799222103102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013012229979 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013012229973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006506114989 + 1006506114990.
It is an arithmetic number, because the mean of its divisors is an integer number (1006506114990).
Almost surely, 22013012229979 is an apocalyptic number.
2013012229979 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013012229979 is an equidigital number, since it uses as much as digits as its factorization.
2013012229979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 47.
The spelling of 2013012229979 in words is "two trillion, thirteen billion, twelve million, two hundred twenty-nine thousand, nine hundred seventy-nine".
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