Base | Representation |
---|---|
bin | 1001001001110111010001… |
… | …10101101010010101011011 |
3 | 2122021102100220002102011110 |
4 | 10210323220311222111123 |
5 | 10114302443010131303 |
6 | 110451352332231403 |
7 | 4145232134255262 |
oct | 444735065522533 |
9 | 78242326072143 |
10 | 20130123130203 |
11 | 6461156796769 |
12 | 231142960b563 |
13 | b3035483a178 |
14 | 4d8435c195d9 |
15 | 24d96d91c703 |
hex | 124ee8d6a55b |
20130123130203 has 4 divisors (see below), whose sum is σ = 26840164173608. Its totient is φ = 13420082086800.
The previous prime is 20130123130151. The next prime is 20130123130207. The reversal of 20130123130203 is 30203132103102.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20130123130203 - 242 = 15732076619099 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20130123130203.
It is not an unprimeable number, because it can be changed into a prime (20130123130207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355020521698 + ... + 3355020521703.
It is an arithmetic number, because the mean of its divisors is an integer number (6710041043402).
Almost surely, 220130123130203 is an apocalyptic number.
20130123130203 is a deficient number, since it is larger than the sum of its proper divisors (6710041043405).
20130123130203 is an equidigital number, since it uses as much as digits as its factorization.
20130123130203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6710041043404.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 20130123130203 its reverse (30203132103102), we get a palindrome (50333255233305).
The spelling of 20130123130203 in words is "twenty trillion, one hundred thirty billion, one hundred twenty-three million, one hundred thirty thousand, two hundred three".
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