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20130123130151 is a prime number
BaseRepresentation
bin1001001001110111010001…
…10101101010010100100111
32122021102100220002102002112
410210323220311222110213
510114302443010131101
6110451352332231235
74145232134255156
oct444735065522447
978242326072075
1020130123130151
116461156796721
12231142960b51b
13b3035483a138
144d8435c1959d
1524d96d91c6bb
hex124ee8d6a527

20130123130151 has 2 divisors, whose sum is σ = 20130123130152. Its totient is φ = 20130123130150.

The previous prime is 20130123130141. The next prime is 20130123130207. The reversal of 20130123130151 is 15103132103102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20130123130151 - 214 = 20130123113767 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20130123130121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065061565075 + 10065061565076.

It is an arithmetic number, because the mean of its divisors is an integer number (10065061565076).

Almost surely, 220130123130151 is an apocalyptic number.

20130123130151 is a deficient number, since it is larger than the sum of its proper divisors (1).

20130123130151 is an equidigital number, since it uses as much as digits as its factorization.

20130123130151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 20130123130151 its reverse (15103132103102), we get a palindrome (35233255233253).

The spelling of 20130123130151 in words is "twenty trillion, one hundred thirty billion, one hundred twenty-three million, one hundred thirty thousand, one hundred fifty-one".