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2013012321211 = 17118412489483
BaseRepresentation
bin11101010010110000111…
…000100110001110111011
321010102221021211020221201
4131102300320212032323
5230440122123234321
64140433132115031
7265302215260423
oct35226070461673
97112837736851
102013012321211
11706793a81361
12286175905a77
13117a9835b318
146d604b05483
153756a565291
hex1d4b0e263bb

2013012321211 has 4 divisors (see below), whose sum is σ = 2131424810712. Its totient is φ = 1894599831712.

The previous prime is 2013012321169. The next prime is 2013012321289. The reversal of 2013012321211 is 1121232103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013012321211 - 217 = 2013012190139 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013012321811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59206244725 + ... + 59206244758.

It is an arithmetic number, because the mean of its divisors is an integer number (532856202678).

Almost surely, 22013012321211 is an apocalyptic number.

2013012321211 is a deficient number, since it is larger than the sum of its proper divisors (118412489501).

2013012321211 is a wasteful number, since it uses less digits than its factorization.

2013012321211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118412489500.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2013012321211 its reverse (1121232103102), we get a palindrome (3134244424313).

The spelling of 2013012321211 in words is "two trillion, thirteen billion, twelve million, three hundred twenty-one thousand, two hundred eleven".

Divisors: 1 17 118412489483 2013012321211