Base | Representation |
---|---|
bin | 10010101111110110… |
… | …010110110111000011 |
3 | 1220221220101121222001 |
4 | 102233312112313003 |
5 | 312211303201040 |
6 | 13125254324431 |
7 | 1311562202503 |
oct | 225766266703 |
9 | 56856347861 |
10 | 20130131395 |
11 | 859aa30730 |
12 | 3a99659717 |
13 | 1b8a63b16a |
14 | d8d6bba03 |
15 | 7cc3c359a |
hex | 4afd96dc3 |
20130131395 has 16 divisors (see below), whose sum is σ = 26396062560. Its totient is φ = 14615712000.
The previous prime is 20130131389. The next prime is 20130131401. The reversal of 20130131395 is 59313103102.
It is an interprime number because it is at equal distance from previous prime (20130131389) and next prime (20130131401).
It is a de Polignac number, because none of the positive numbers 2k-20130131395 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 271440 + ... + 337549.
It is an arithmetic number, because the mean of its divisors is an integer number (1649753910).
Almost surely, 220130131395 is an apocalyptic number.
20130131395 is a deficient number, since it is larger than the sum of its proper divisors (6265931165).
20130131395 is a wasteful number, since it uses less digits than its factorization.
20130131395 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 609606.
The product of its (nonzero) digits is 2430, while the sum is 28.
Adding to 20130131395 its reverse (59313103102), we get a palindrome (79443234497).
It can be divided in two parts, 20130 and 131395, that added together give a triangular number (151525 = T550).
The spelling of 20130131395 in words is "twenty billion, one hundred thirty million, one hundred thirty-one thousand, three hundred ninety-five".
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