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2013013200103 = 7135398011387
BaseRepresentation
bin11101010010110000111…
…011111100110011100111
321010102221100110220120021
4131102300323330303213
5230440122334400403
64140433203020011
7265302225610663
oct35226073746347
97112840426507
102013013200103
11706794521714
1228617606a607
13117a985a8389
146d604c938a3
153756a68a8bd
hex1d4b0efcce7

2013013200103 has 8 divisors (see below), whose sum is σ = 2041942573440. Its totient is φ = 1984099856760.

The previous prime is 2013013200061. The next prime is 2013013200119. The reversal of 2013013200103 is 3010023103102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013013200103 - 225 = 2012979645671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013013200203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3754425 + ... + 4256962.

It is an arithmetic number, because the mean of its divisors is an integer number (255242821680).

Almost surely, 22013013200103 is an apocalyptic number.

2013013200103 is a deficient number, since it is larger than the sum of its proper divisors (28929373337).

2013013200103 is an equidigital number, since it uses as much as digits as its factorization.

2013013200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8014997.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 2013013200103 its reverse (3010023103102), we get a palindrome (5023036303205).

The spelling of 2013013200103 in words is "two trillion, thirteen billion, thirteen million, two hundred thousand, one hundred three".

Divisors: 1 71 3539 251269 8011387 568808477 28352298593 2013013200103