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20130132201103 = 114431759165621
BaseRepresentation
bin1001001001110111010010…
…11000010000111010001111
32122021102101112011021002201
410210323221120100322033
510114303002320413403
6110451353254502331
74145232304335121
oct444735130207217
978242345137081
1020130132201103
116461160921881
1223114306649a7
13b30356694b72
144d84370db211
1524d96e61021d
hex124ee9610e8f

20130132201103 has 4 divisors (see below), whose sum is σ = 20131891378168. Its totient is φ = 20128373024040.

The previous prime is 20130132201077. The next prime is 20130132201107. The reversal of 20130132201103 is 30110223103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20130132201103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130132201107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 879571368 + ... + 879594253.

It is an arithmetic number, because the mean of its divisors is an integer number (5032972844542).

Almost surely, 220130132201103 is an apocalyptic number.

20130132201103 is a deficient number, since it is larger than the sum of its proper divisors (1759177065).

20130132201103 is a wasteful number, since it uses less digits than its factorization.

20130132201103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1759177064.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20130132201103 its reverse (30110223103102), we get a palindrome (50240355304205).

The spelling of 20130132201103 in words is "twenty trillion, one hundred thirty billion, one hundred thirty-two million, two hundred one thousand, one hundred three".

Divisors: 1 11443 1759165621 20130132201103