Base | Representation |
---|---|
bin | 1001001001110111010100… |
… | …00010010000111100111011 |
3 | 2122021102102021212122021122 |
4 | 10210323222002100330323 |
5 | 10114303013130230243 |
6 | 110451354330455455 |
7 | 4145232500042645 |
oct | 444735202207473 |
9 | 78242367778248 |
10 | 20130143211323 |
11 | 6461167061a32 |
12 | 231143429458b |
13 | b30358a4b4a2 |
14 | 4d8438765895 |
15 | 24d970587668 |
hex | 124eea090f3b |
20130143211323 has 4 divisors (see below), whose sum is σ = 20137020612000. Its totient is φ = 20123265810648.
The previous prime is 20130143211289. The next prime is 20130143211329. The reversal of 20130143211323 is 32311234103102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20130143211323 - 210 = 20130143210299 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20130143211292 and 20130143211301.
It is not an unprimeable number, because it can be changed into a prime (20130143211329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3438695948 + ... + 3438701801.
It is an arithmetic number, because the mean of its divisors is an integer number (5034255153000).
Almost surely, 220130143211323 is an apocalyptic number.
20130143211323 is a deficient number, since it is larger than the sum of its proper divisors (6877400677).
20130143211323 is an equidigital number, since it uses as much as digits as its factorization.
20130143211323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6877400676.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 20130143211323 its reverse (32311234103102), we get a palindrome (52441377314425).
The spelling of 20130143211323 in words is "twenty trillion, one hundred thirty billion, one hundred forty-three million, two hundred eleven thousand, three hundred twenty-three".
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