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20130153577115 = 54026030715423
BaseRepresentation
bin1001001001110111010101…
…01001110011101010011011
32122021102110000101021110212
410210323222221303222123
510114303023303431430
6110451355341001335
74145232654124631
oct444735251635233
978242400337425
1020130153577115
1164611719a19aa
12231143785324b
13b3035ac3a6aa
144d8439ca3351
1524d971433b95
hex124eeaa73a9b

20130153577115 has 4 divisors (see below), whose sum is σ = 24156184292544. Its totient is φ = 16104122861688.

The previous prime is 20130153577109. The next prime is 20130153577117. The reversal of 20130153577115 is 51177535103102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20130153577115 - 226 = 20130086468251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130153577117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2013015357707 + ... + 2013015357716.

It is an arithmetic number, because the mean of its divisors is an integer number (6039046073136).

Almost surely, 220130153577115 is an apocalyptic number.

20130153577115 is a deficient number, since it is larger than the sum of its proper divisors (4026030715429).

20130153577115 is an equidigital number, since it uses as much as digits as its factorization.

20130153577115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4026030715428.

The product of its (nonzero) digits is 110250, while the sum is 41.

The spelling of 20130153577115 in words is "twenty trillion, one hundred thirty billion, one hundred fifty-three million, five hundred seventy-seven thousand, one hundred fifteen".

Divisors: 1 5 4026030715423 20130153577115