201302011012231 has 4 divisors (see below), whose sum is σ = 201302070628464. Its totient is φ = 201301951396000.

The previous prime is 201302011012183. The next prime is 201302011012273. The reversal of 201302011012231 is 132210110203102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201302011012231 - 2¹⁵ = 201302010979463 is a prime.

It is a super-2 number, since 2×201302011012231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201302011012199 and 201302011012208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201302011012331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24418315 + ... + 31604716.

It is an arithmetic number, because the mean of its divisors is an integer number (50325517657116).

Almost surely, 2^{201302011012231} is an apocalyptic number.

201302011012231 is a deficient number, since it is larger than the sum of its proper divisors (59616233).

201302011012231 is an equidigital number, since it uses as much as digits as its factorization.

201302011012231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59616232.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 201302011012231 its reverse (132210110203102), we get a palindrome (333512121215333).

The spelling of 201302011012231 in words is "two hundred one trillion, three hundred two billion, eleven million, twelve thousand, two hundred thirty-one".