Base | Representation |
---|---|
bin | 10010101111110110… |
… | …100111111000010011 |
3 | 1220221220112011120222 |
4 | 102233312213320103 |
5 | 312211312413412 |
6 | 13125300023255 |
7 | 1311562612652 |
oct | 225766477023 |
9 | 56856464528 |
10 | 20130201107 |
11 | 859aa79045 |
12 | 3a99691b2b |
13 | 1b8a663b03 |
14 | d8d6d9199 |
15 | 7cc3d9072 |
hex | 4afda7e13 |
20130201107 has 2 divisors, whose sum is σ = 20130201108. Its totient is φ = 20130201106.
The previous prime is 20130201103. The next prime is 20130201139. The reversal of 20130201107 is 70110203102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20130201107 - 22 = 20130201103 is a prime.
It is not a weakly prime, because it can be changed into another prime (20130201103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065100553 + 10065100554.
It is an arithmetic number, because the mean of its divisors is an integer number (10065100554).
Almost surely, 220130201107 is an apocalyptic number.
20130201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130201107 is an equidigital number, since it uses as much as digits as its factorization.
20130201107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 20130201107 its reverse (70110203102), we get a palindrome (90240404209).
The spelling of 20130201107 in words is "twenty billion, one hundred thirty million, two hundred one thousand, one hundred seven".
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