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201302312011 = 437114605301
BaseRepresentation
bin1011101101111010001…
…1011000010001001011
3201020121002210222201121
42323132203120101023
511244231342441021
6232251011100111
720354313264013
oct2733643302113
9636532728647
10201302312011
117840a9a8519
123301b8a1637
1315ca10865b8
149a59044c43
15538296e741
hex2ede8d844b

201302312011 has 4 divisors (see below), whose sum is σ = 201306961024. Its totient is φ = 201297663000.

The previous prime is 201302311979. The next prime is 201302312021. The reversal of 201302312011 is 110213203102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110213203102 = 255106601551.

It is a cyclic number.

It is not a de Polignac number, because 201302312011 - 25 = 201302311979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201302312021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2258940 + ... + 2346361.

It is an arithmetic number, because the mean of its divisors is an integer number (50326740256).

Almost surely, 2201302312011 is an apocalyptic number.

201302312011 is a deficient number, since it is larger than the sum of its proper divisors (4649013).

201302312011 is an equidigital number, since it uses as much as digits as its factorization.

201302312011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4649012.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 201302312011 its reverse (110213203102), we get a palindrome (311515515113).

The spelling of 201302312011 in words is "two hundred one billion, three hundred two million, three hundred twelve thousand, eleven".

Divisors: 1 43711 4605301 201302312011