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2013030330011 = 4253473320087
BaseRepresentation
bin11101010010110001111…
…101010010111010011011
321010102222112201012101022
4131102301331102322123
5230440141231030021
64140435014113055
7265302524324261
oct35226175227233
97112875635338
102013030330011
117067a3161668
1228617b94b78b
13117a9bcc530c
146d607272431
153756be211ab
hex1d4b1f52e9b

2013030330011 has 4 divisors (see below), whose sum is σ = 2013503654352. Its totient is φ = 2012557005672.

The previous prime is 2013030329977. The next prime is 2013030330037. The reversal of 2013030330011 is 1100330303102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013030330011 - 214 = 2013030313627 is a prime.

It is a super-2 number, since 2×20130303300112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013030330211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236655791 + ... + 236664296.

It is an arithmetic number, because the mean of its divisors is an integer number (503375913588).

Almost surely, 22013030330011 is an apocalyptic number.

2013030330011 is a deficient number, since it is larger than the sum of its proper divisors (473324341).

2013030330011 is an equidigital number, since it uses as much as digits as its factorization.

2013030330011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 473324340.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 2013030330011 its reverse (1100330303102), we get a palindrome (3113360633113).

The spelling of 2013030330011 in words is "two trillion, thirteen billion, thirty million, three hundred thirty thousand, eleven".

Divisors: 1 4253 473320087 2013030330011