Base | Representation |
---|---|
bin | 1001001001110111100111… |
… | …01000000101010011100010 |
3 | 2122021102211111122122112112 |
4 | 10210323303220011103202 |
5 | 10114303330323320114 |
6 | 110451422315355322 |
7 | 4145236462535363 |
oct | 444736350052342 |
9 | 78242744578475 |
10 | 20130304120034 |
11 | 6461239975039 |
12 | 231147a152b42 |
13 | b30383199744 |
14 | 4d8451c8db6a |
15 | 24d97e76e13e |
hex | 124ef3a054e2 |
20130304120034 has 4 divisors (see below), whose sum is σ = 30195456180054. Its totient is φ = 10065152060016.
The previous prime is 20130304120021. The next prime is 20130304120063. The reversal of 20130304120034 is 43002140303102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 18062474500009 + 2067829620025 = 4249997^2 + 1437995^2 .
It is a super-2 number, since 2×201303041200342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20130304119991 and 20130304120009.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5032576030007 + ... + 5032576030010.
Almost surely, 220130304120034 is an apocalyptic number.
20130304120034 is a deficient number, since it is larger than the sum of its proper divisors (10065152060020).
20130304120034 is a wasteful number, since it uses less digits than its factorization.
20130304120034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10065152060019.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 20130304120034 its reverse (43002140303102), we get a palindrome (63132444423136).
The spelling of 20130304120034 in words is "twenty trillion, one hundred thirty billion, three hundred four million, one hundred twenty thousand, thirty-four".
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