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20130310130411 = 131548485394647
BaseRepresentation
bin1001001001110111100111…
…11111000000101011101011
32122021102211220222000020002
410210323303333000223223
510114303333343133121
6110451423052253215
74145236564610345
oct444736377005353
978242756860202
1020130310130411
1164612422aa798
12231148017120b
13b303844c2390
144d84529b6295
1524d980059e0b
hex124ef3fc0aeb

20130310130411 has 4 divisors (see below), whose sum is σ = 21678795525072. Its totient is φ = 18581824735752.

The previous prime is 20130310130401. The next prime is 20130310130519. The reversal of 20130310130411 is 11403101303102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20130310130411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20130310130401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 774242697311 + ... + 774242697336.

It is an arithmetic number, because the mean of its divisors is an integer number (5419698881268).

Almost surely, 220130310130411 is an apocalyptic number.

20130310130411 is a deficient number, since it is larger than the sum of its proper divisors (1548485394661).

20130310130411 is a wasteful number, since it uses less digits than its factorization.

20130310130411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1548485394660.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 20130310130411 its reverse (11403101303102), we get a palindrome (31533411433513).

The spelling of 20130310130411 in words is "twenty trillion, one hundred thirty billion, three hundred ten million, one hundred thirty thousand, four hundred eleven".

Divisors: 1 13 1548485394647 20130310130411