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201303113131997 is a prime number
BaseRepresentation
bin101101110001010110001000…
…100011001110011111011101
3222101202101112001220000001122
4231301112020203032133131
5202341122233430210442
61552045212402220325
760254445542216612
oct5561261043163735
9871671461800048
10201303113131997
11591611974466a8
121a6b1a853546a5
138842a5732b656
14379d1a0824509
151841551453dd2
hexb715888ce7dd

201303113131997 has 2 divisors, whose sum is σ = 201303113131998. Its totient is φ = 201303113131996.

The previous prime is 201303113131993. The next prime is 201303113132029. The reversal of 201303113131997 is 799131311303102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136957142831161 + 64345970300836 = 11702869^2 + 8021594^2 .

It is a cyclic number.

It is not a de Polignac number, because 201303113131997 - 22 = 201303113131993 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201303113131993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651556565998 + 100651556565999.

It is an arithmetic number, because the mean of its divisors is an integer number (100651556565999).

Almost surely, 2201303113131997 is an apocalyptic number.

It is an amenable number.

201303113131997 is a deficient number, since it is larger than the sum of its proper divisors (1).

201303113131997 is an equidigital number, since it uses as much as digits as its factorization.

201303113131997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 91854, while the sum is 44.

The spelling of 201303113131997 in words is "two hundred one trillion, three hundred three billion, one hundred thirteen million, one hundred thirty-one thousand, nine hundred ninety-seven".