Base | Representation |
---|---|
bin | 101101110001010110001000… |
… | …100011001110011111011101 |
3 | 222101202101112001220000001122 |
4 | 231301112020203032133131 |
5 | 202341122233430210442 |
6 | 1552045212402220325 |
7 | 60254445542216612 |
oct | 5561261043163735 |
9 | 871671461800048 |
10 | 201303113131997 |
11 | 591611974466a8 |
12 | 1a6b1a853546a5 |
13 | 8842a5732b656 |
14 | 379d1a0824509 |
15 | 1841551453dd2 |
hex | b715888ce7dd |
201303113131997 has 2 divisors, whose sum is σ = 201303113131998. Its totient is φ = 201303113131996.
The previous prime is 201303113131993. The next prime is 201303113132029. The reversal of 201303113131997 is 799131311303102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 136957142831161 + 64345970300836 = 11702869^2 + 8021594^2 .
It is a cyclic number.
It is not a de Polignac number, because 201303113131997 - 22 = 201303113131993 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201303113131993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100651556565998 + 100651556565999.
It is an arithmetic number, because the mean of its divisors is an integer number (100651556565999).
Almost surely, 2201303113131997 is an apocalyptic number.
It is an amenable number.
201303113131997 is a deficient number, since it is larger than the sum of its proper divisors (1).
201303113131997 is an equidigital number, since it uses as much as digits as its factorization.
201303113131997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91854, while the sum is 44.
The spelling of 201303113131997 in words is "two hundred one trillion, three hundred three billion, one hundred thirteen million, one hundred thirty-one thousand, nine hundred ninety-seven".
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