Search a number
-
+
2013032211301 is a prime number
BaseRepresentation
bin11101010010110010000…
…100011110001101100101
321010102222200020210000201
4131102302010132031211
5230440142221230201
64140435122310501
7265302546321136
oct35226204361545
97112880223021
102013032211301
117067a4227051
122861804b8431
13117a9c5036c7
146d607601c8d
153756c193801
hex1d4b211e365

2013032211301 has 2 divisors, whose sum is σ = 2013032211302. Its totient is φ = 2013032211300.

The previous prime is 2013032211277. The next prime is 2013032211343. The reversal of 2013032211301 is 1031122303102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1854297699076 + 158734512225 = 1361726^2 + 398415^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013032211301 - 215 = 2013032178533 is a prime.

It is a super-2 number, since 2×20130322113012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013032211601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006516105650 + 1006516105651.

It is an arithmetic number, because the mean of its divisors is an integer number (1006516105651).

Almost surely, 22013032211301 is an apocalyptic number.

It is an amenable number.

2013032211301 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013032211301 is an equidigital number, since it uses as much as digits as its factorization.

2013032211301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2013032211301 its reverse (1031122303102), we get a palindrome (3044154514403).

The spelling of 2013032211301 in words is "two trillion, thirteen billion, thirty-two million, two hundred eleven thousand, three hundred one".