Base | Representation |
---|---|
bin | 1001001001110111110010… |
… | …10110101100010001010111 |
3 | 2122021110002012111020212101 |
4 | 10210323321112230101113 |
5 | 10114304024424134333 |
6 | 110451440031302531 |
7 | 4145242040444023 |
oct | 444737126542127 |
9 | 78243065436771 |
10 | 20130400224343 |
11 | 6461289145692 |
12 | 23114a637aa47 |
13 | b3039a077cb6 |
14 | 4d8460949383 |
15 | 24d987e0467d |
hex | 124ef95ac457 |
20130400224343 has 2 divisors, whose sum is σ = 20130400224344. Its totient is φ = 20130400224342.
The previous prime is 20130400224251. The next prime is 20130400224353. The reversal of 20130400224343 is 34342200403102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20130400224343 - 213 = 20130400216151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20130400224353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065200112171 + 10065200112172.
It is an arithmetic number, because the mean of its divisors is an integer number (10065200112172).
Almost surely, 220130400224343 is an apocalyptic number.
20130400224343 is a deficient number, since it is larger than the sum of its proper divisors (1).
20130400224343 is an equidigital number, since it uses as much as digits as its factorization.
20130400224343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 20130400224343 its reverse (34342200403102), we get a palindrome (54472600627445).
The spelling of 20130400224343 in words is "twenty trillion, one hundred thirty billion, four hundred million, two hundred twenty-four thousand, three hundred forty-three".
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