Base | Representation |
---|---|
bin | 1011101101111010101… |
… | …0001111100000110011 |
3 | 201020121020012101200120 |
4 | 2323132222033200303 |
5 | 11244232323024110 |
6 | 232251113421323 |
7 | 20354334466230 |
oct | 2733652174063 |
9 | 636536171616 |
10 | 201304111155 |
11 | 78410a17214 |
12 | 3302040a843 |
13 | 15ca1566494 |
14 | 9a59392787 |
15 | 5382bc7870 |
hex | 2edea8f833 |
201304111155 has 64 divisors (see below), whose sum is σ = 383890956288. Its totient is φ = 88137953280.
The previous prime is 201304111121. The next prime is 201304111189. The reversal of 201304111155 is 551111403102.
It is an interprime number because it is at equal distance from previous prime (201304111121) and next prime (201304111189).
It is not a de Polignac number, because 201304111155 - 213 = 201304102963 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3052 + ... + 634521.
It is an arithmetic number, because the mean of its divisors is an integer number (5998296192).
Almost surely, 2201304111155 is an apocalyptic number.
201304111155 is a deficient number, since it is larger than the sum of its proper divisors (182586845133).
201304111155 is a wasteful number, since it uses less digits than its factorization.
201304111155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 637716.
The product of its (nonzero) digits is 600, while the sum is 24.
Adding to 201304111155 its reverse (551111403102), we get a palindrome (752415514257).
The spelling of 201304111155 in words is "two hundred one billion, three hundred four million, one hundred eleven thousand, one hundred fifty-five".
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