Base | Representation |
---|---|
bin | 11101010010110010100… |
… | …110100101011000000100 |
3 | 21010110000022002002110202 |
4 | 131102302212211120010 |
5 | 230440202013403130 |
6 | 4140440042110032 |
7 | 265303015323614 |
oct | 35226246453004 |
9 | 7113008062422 |
10 | 2013041153540 |
11 | 7067a928452a |
12 | 2861834ab318 |
13 | 117aa1314981 |
14 | 6d60888ca44 |
15 | 3756cd5d145 |
hex | 1d4b29a5604 |
2013041153540 has 24 divisors (see below), whose sum is σ = 4229415980160. Its totient is φ = 804829879008.
The previous prime is 2013041153477. The next prime is 2013041153603. The reversal of 2013041153540 is 453511403102.
It is an interprime number because it is at equal distance from previous prime (2013041153477) and next prime (2013041153603).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24118700 + ... + 24202019.
It is an arithmetic number, because the mean of its divisors is an integer number (176225665840).
Almost surely, 22013041153540 is an apocalyptic number.
2013041153540 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2013041153540 is an abundant number, since it is smaller than the sum of its proper divisors (2216374826620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013041153540 is a wasteful number, since it uses less digits than its factorization.
2013041153540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48322811 (or 48322809 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 2013041153540 its reverse (453511403102), we get a palindrome (2466552556642).
The spelling of 2013041153540 in words is "two trillion, thirteen billion, forty-one million, one hundred fifty-three thousand, five hundred forty".
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