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201304451 is a prime number
BaseRepresentation
bin10111111111110…
…10100110000011
3112000210022210102
423333322212003
5403013220301
631550353015
74663026305
oct1377724603
9460708712
10201304451
11a36a4017
12574bb76b
1332922c7a
141ca41975
1512a15b6b
hexbffa983

201304451 has 2 divisors, whose sum is σ = 201304452. Its totient is φ = 201304450.

The previous prime is 201304447. The next prime is 201304471. The reversal of 201304451 is 154403102.

It is an a-pointer prime, because the next prime (201304471) can be obtained adding 201304451 to its sum of digits (20).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201304451 - 22 = 201304447 is a prime.

It is a super-3 number, since 3×2013044513 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (201304471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100652225 + 100652226.

It is an arithmetic number, because the mean of its divisors is an integer number (100652226).

Almost surely, 2201304451 is an apocalyptic number.

201304451 is a deficient number, since it is larger than the sum of its proper divisors (1).

201304451 is an equidigital number, since it uses as much as digits as its factorization.

201304451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 20.

The square root of 201304451 is about 14188.1799748946. The cubic root of 201304451 is about 586.0722060769.

Adding to 201304451 its reverse (154403102), we get a palindrome (355707553).

The spelling of 201304451 in words is "two hundred one million, three hundred four thousand, four hundred fifty-one".