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2013064541041 is a prime number
BaseRepresentation
bin11101010010110011111…
…111110011001101110001
321010110001221002022002111
4131102303333303031301
5230440224010303131
64140442235245321
7265303421162011
oct35226377631561
97113057068074
102013064541041
117068104a8944
1228618b2a9841
13117aa6112c28
146d60ba19c41
153756ee2cab1
hex1d4b3ff3371

2013064541041 has 2 divisors, whose sum is σ = 2013064541042. Its totient is φ = 2013064541040.

The previous prime is 2013064541017. The next prime is 2013064541129. The reversal of 2013064541041 is 1401454603102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1281150070641 + 731914470400 = 1131879^2 + 855520^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013064541041 - 211 = 2013064538993 is a prime.

It is a super-2 number, since 2×20130645410412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013064540994 and 2013064541012.

It is not a weakly prime, because it can be changed into another prime (2013064544041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006532270520 + 1006532270521.

It is an arithmetic number, because the mean of its divisors is an integer number (1006532270521).

Almost surely, 22013064541041 is an apocalyptic number.

It is an amenable number.

2013064541041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013064541041 is an equidigital number, since it uses as much as digits as its factorization.

2013064541041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

The spelling of 2013064541041 in words is "two trillion, thirteen billion, sixty-four million, five hundred forty-one thousand, forty-one".