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2013064541129 is a prime number
BaseRepresentation
bin11101010010110011111…
…111110011001111001001
321010110001221002022012202
4131102303333303033021
5230440224010304004
64140442235245545
7265303421162165
oct35226377631711
97113057068182
102013064541129
117068104a8a14
1228618b2a98b5
13117aa6112c95
146d60ba19ca5
153756ee2cb1e
hex1d4b3ff33c9

2013064541129 has 2 divisors, whose sum is σ = 2013064541130. Its totient is φ = 2013064541128.

The previous prime is 2013064541041. The next prime is 2013064541167. The reversal of 2013064541129 is 9211454603102.

It is an a-pointer prime, because the next prime (2013064541167) can be obtained adding 2013064541129 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1945391721529 + 67672819600 = 1394773^2 + 260140^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013064541129 - 28 = 2013064540873 is a prime.

It is a super-2 number, since 2×20130645411292 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013064541092 and 2013064541101.

It is not a weakly prime, because it can be changed into another prime (2013064543129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006532270564 + 1006532270565.

It is an arithmetic number, because the mean of its divisors is an integer number (1006532270565).

Almost surely, 22013064541129 is an apocalyptic number.

It is an amenable number.

2013064541129 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013064541129 is an equidigital number, since it uses as much as digits as its factorization.

2013064541129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 2013064541129 in words is "two trillion, thirteen billion, sixty-four million, five hundred forty-one thousand, one hundred twenty-nine".