Base | Representation |
---|---|
bin | 11101010010110110001… |
… | …100111011000010101011 |
3 | 21010110011111200210211001 |
4 | 131102312030323002223 |
5 | 230440312443113103 |
6 | 4140450040215431 |
7 | 265304350501210 |
oct | 35226614730253 |
9 | 7113144623731 |
10 | 2013101535403 |
11 | 70682a3762a2 |
12 | 28619b76a577 |
13 | 117ab099669a |
14 | 6d6128c9b07 |
15 | 375732d901d |
hex | 1d4b633b0ab |
2013101535403 has 8 divisors (see below), whose sum is σ = 2323024241408. Its totient is φ = 1708763022504.
The previous prime is 2013101535359. The next prime is 2013101535427. The reversal of 2013101535403 is 3045351013102.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2013101535403 - 229 = 2012564664491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013101535493) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1396047501 + ... + 1396048942.
It is an arithmetic number, because the mean of its divisors is an integer number (290378030176).
Almost surely, 22013101535403 is an apocalyptic number.
2013101535403 is a deficient number, since it is larger than the sum of its proper divisors (309922706005).
2013101535403 is a wasteful number, since it uses less digits than its factorization.
2013101535403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2792096553.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 2013101535403 its reverse (3045351013102), we get a palindrome (5058452548505).
The spelling of 2013101535403 in words is "two trillion, thirteen billion, one hundred one million, five hundred thirty-five thousand, four hundred three".
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