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2013101535403 = 71032792096443
BaseRepresentation
bin11101010010110110001…
…100111011000010101011
321010110011111200210211001
4131102312030323002223
5230440312443113103
64140450040215431
7265304350501210
oct35226614730253
97113144623731
102013101535403
1170682a3762a2
1228619b76a577
13117ab099669a
146d6128c9b07
15375732d901d
hex1d4b633b0ab

2013101535403 has 8 divisors (see below), whose sum is σ = 2323024241408. Its totient is φ = 1708763022504.

The previous prime is 2013101535359. The next prime is 2013101535427. The reversal of 2013101535403 is 3045351013102.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013101535403 - 229 = 2012564664491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013101535493) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1396047501 + ... + 1396048942.

It is an arithmetic number, because the mean of its divisors is an integer number (290378030176).

Almost surely, 22013101535403 is an apocalyptic number.

2013101535403 is a deficient number, since it is larger than the sum of its proper divisors (309922706005).

2013101535403 is a wasteful number, since it uses less digits than its factorization.

2013101535403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2792096553.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 2013101535403 its reverse (3045351013102), we get a palindrome (5058452548505).

The spelling of 2013101535403 in words is "two trillion, thirteen billion, one hundred one million, five hundred thirty-five thousand, four hundred three".

Divisors: 1 7 103 721 2792096443 19544675101 287585933629 2013101535403