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2013102021101 = 5934120373239
BaseRepresentation
bin11101010010110110001…
…110110001100111101101
321010110011112121111001212
4131102312032301213231
5230440313104133401
64140450054444205
7265304354563223
oct35226616614755
97113145544055
102013102021101
1170682a6781a6
1228619b963665
13117ab0b06792
146d6129b4b13
1537573382dbb
hex1d4b63b19ed

2013102021101 has 4 divisors (see below), whose sum is σ = 2047222394400. Its totient is φ = 1978981647804.

The previous prime is 2013102021089. The next prime is 2013102021149. The reversal of 2013102021101 is 1011202013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013102021101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013102021181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17060186561 + ... + 17060186678.

It is an arithmetic number, because the mean of its divisors is an integer number (511805598600).

Almost surely, 22013102021101 is an apocalyptic number.

It is an amenable number.

2013102021101 is a deficient number, since it is larger than the sum of its proper divisors (34120373299).

2013102021101 is an equidigital number, since it uses as much as digits as its factorization.

2013102021101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34120373298.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 2013102021101 its reverse (1011202013102), we get a palindrome (3024304034203).

The spelling of 2013102021101 in words is "two trillion, thirteen billion, one hundred two million, twenty-one thousand, one hundred one".

Divisors: 1 59 34120373239 2013102021101