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2013102113 = 11183009283
BaseRepresentation
bin111011111111101…
…1000000000100001
312012022000011221112
41313333120000201
513110323231423
6531431433105
7100613041241
oct16777300041
95168004845
102013102113
11943386460
12482225795
132610b3ba9
14151509b21
15bbaeea78
hex77fd8021

2013102113 has 4 divisors (see below), whose sum is σ = 2196111408. Its totient is φ = 1830092820.

The previous prime is 2013102103. The next prime is 2013102181. The reversal of 2013102113 is 3112013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013102113 - 214 = 2013085729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013102103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91504631 + ... + 91504652.

It is an arithmetic number, because the mean of its divisors is an integer number (549027852).

Almost surely, 22013102113 is an apocalyptic number.

It is an amenable number.

2013102113 is a deficient number, since it is larger than the sum of its proper divisors (183009295).

2013102113 is a wasteful number, since it uses less digits than its factorization.

2013102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183009294.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2013102113 is about 44867.6064995671. The cubic root of 2013102113 is about 1262.6663350820. Note that the first 3 decimals are identical.

Adding to 2013102113 its reverse (3112013102), we get a palindrome (5125115215).

The spelling of 2013102113 in words is "two billion, thirteen million, one hundred two thousand, one hundred thirteen".

Divisors: 1 11 183009283 2013102113