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2013102203113 = 6783362003633
BaseRepresentation
bin11101010010110110001…
…111011110000011101001
321010110011112221201202001
4131102312033132003221
5230440313130444423
64140450102411001
7265304356251661
oct35226617360351
97113145851661
102013102203113
1170682a791a21
1228619ba30a61
13117ab0b6b591
146d612a211a1
15375733bbcad
hex1d4b63de0e9

2013102203113 has 8 divisors (see below), whose sum is σ = 2067764757408. Its totient is φ = 1959163656384.

The previous prime is 2013102203093. The next prime is 2013102203137. The reversal of 2013102203113 is 3113022013102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013102203113 - 237 = 1875663249641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013102203153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 180996256 + ... + 181007377.

It is an arithmetic number, because the mean of its divisors is an integer number (258470594676).

Almost surely, 22013102203113 is an apocalyptic number.

It is an amenable number.

2013102203113 is a deficient number, since it is larger than the sum of its proper divisors (54662554295).

2013102203113 is an equidigital number, since it uses as much as digits as its factorization.

2013102203113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 362003783.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2013102203113 its reverse (3113022013102), we get a palindrome (5126124216215).

The spelling of 2013102203113 in words is "two trillion, thirteen billion, one hundred two million, two hundred three thousand, one hundred thirteen".

Divisors: 1 67 83 5561 362003633 24254243411 30046301539 2013102203113