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201310322113 = 1631235032651
BaseRepresentation
bin1011101101111100000…
…1111011110111000001
3201020121122212221112001
42323133001323313001
511244240420301423
6232251454504001
720354441335045
oct2733701736701
9636548787461
10201310322113
117841447963a
1233022505001
1315ca292c4c4
149a5a12c025
155383502cad
hex2edf07bdc1

201310322113 has 4 divisors (see below), whose sum is σ = 202545354928. Its totient is φ = 200075289300.

The previous prime is 201310322099. The next prime is 201310322119. The reversal of 201310322113 is 311223013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201310322113 - 217 = 201310191041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201310322119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 617516163 + ... + 617516488.

It is an arithmetic number, because the mean of its divisors is an integer number (50636338732).

Almost surely, 2201310322113 is an apocalyptic number.

It is an amenable number.

201310322113 is a deficient number, since it is larger than the sum of its proper divisors (1235032815).

201310322113 is a wasteful number, since it uses less digits than its factorization.

201310322113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1235032814.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 201310322113 its reverse (311223013102), we get a palindrome (512533335215).

The spelling of 201310322113 in words is "two hundred one billion, three hundred ten million, three hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 163 1235032651 201310322113