Base | Representation |
---|---|
bin | 11101010010110110010… |
… | …011011110001101100111 |
3 | 21010110011121221000222211 |
4 | 131102312103132031213 |
5 | 230440313413033302 |
6 | 4140450141104251 |
7 | 265304401211626 |
oct | 35226623361547 |
9 | 7113147830884 |
10 | 2013103252327 |
11 | 706830339242 |
12 | 2861a0258087 |
13 | 117ab114800b |
14 | 6d612c156bd |
15 | 37573527ad7 |
hex | 1d4b64de367 |
2013103252327 has 2 divisors, whose sum is σ = 2013103252328. Its totient is φ = 2013103252326.
The previous prime is 2013103252289. The next prime is 2013103252337. The reversal of 2013103252327 is 7232523013102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013103252327 - 215 = 2013103219559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013103252337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006551626163 + 1006551626164.
It is an arithmetic number, because the mean of its divisors is an integer number (1006551626164).
Almost surely, 22013103252327 is an apocalyptic number.
2013103252327 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013103252327 is an equidigital number, since it uses as much as digits as its factorization.
2013103252327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 2013103252327 its reverse (7232523013102), we get a palindrome (9245626265429).
The spelling of 2013103252327 in words is "two trillion, thirteen billion, one hundred three million, two hundred fifty-two thousand, three hundred twenty-seven".
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