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2013110103 = 32069324329
BaseRepresentation
bin111011111111101…
…1001111101010111
312012022000120220110
41313333121331113
513110324010403
6531431534103
7100613103444
oct16777317527
95168016813
102013110103
11943391464
1248222a333
132610b7714
1415150c9cb
15bbb02103
hex77fd9f57

2013110103 has 8 divisors (see below), whose sum is σ = 2685452400. Its totient is φ = 1341420608.

The previous prime is 2013110087. The next prime is 2013110107. The reversal of 2013110103 is 3010113102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013110103 - 24 = 2013110087 is a prime.

It is a super-2 number, since 2×20131101032 = 8105224573601341218, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013110107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155958 + ... + 168371.

It is an arithmetic number, because the mean of its divisors is an integer number (335681550).

Almost surely, 22013110103 is an apocalyptic number.

2013110103 is a deficient number, since it is larger than the sum of its proper divisors (672342297).

2013110103 is a wasteful number, since it uses less digits than its factorization.

2013110103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 326401.

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 2013110103 is about 44867.6955392184. The cubic root of 2013110103 is about 1262.6680055869.

Adding to 2013110103 its reverse (3010113102), we get a palindrome (5023223205).

Subtracting 2013110103 from its reverse (3010113102), we obtain a cube (997002999 = 9993).

The spelling of 2013110103 in words is "two billion, thirteen million, one hundred ten thousand, one hundred three".

Divisors: 1 3 2069 6207 324329 972987 671036701 2013110103