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2013110153 = 7931181937
BaseRepresentation
bin111011111111101…
…1001111110001001
312012022000120222022
41313333121332021
513110324011103
6531431534225
7100613103545
oct16777317611
95168016868
102013110153
119433914aa
1248222a375
132610b7752
1415150ca25
15bbb02138
hex77fd9f89

2013110153 has 8 divisors (see below), whose sum is σ = 2045172480. Its totient is φ = 1981212480.

The previous prime is 2013110129. The next prime is 2013110179. The reversal of 2013110153 is 3510113102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013110153 - 28 = 2013109897 is a prime.

It is a super-2 number, since 2×20131101532 = 8105224976223366818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013110053) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16400 + ... + 65537.

It is an arithmetic number, because the mean of its divisors is an integer number (255646560).

Almost surely, 22013110153 is an apocalyptic number.

It is an amenable number.

2013110153 is a deficient number, since it is larger than the sum of its proper divisors (32062327).

2013110153 is an equidigital number, since it uses as much as digits as its factorization.

2013110153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82327.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 2013110153 is about 44867.6960964122. The cubic root of 2013110153 is about 1262.6680160406.

Adding to 2013110153 its reverse (3510113102), we get a palindrome (5523223255).

The spelling of 2013110153 in words is "two billion, thirteen million, one hundred ten thousand, one hundred fifty-three".

Divisors: 1 79 311 24569 81937 6473023 25482407 2013110153