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20131111031027 is a prime number
BaseRepresentation
bin1001001001111001000111…
…01110001101000011110011
32122021111220201222222022212
410210330203232031003303
510114312003410443102
6110452034342322335
74145265461264513
oct444744356150363
978244821888285
1020131111031027
1164616133a6227
1223116644293ab
13b304813cc179
144d84cb0d7843
1524d9ca50dc52
hex124f23b8d0f3

20131111031027 has 2 divisors, whose sum is σ = 20131111031028. Its totient is φ = 20131111031026.

The previous prime is 20131111030981. The next prime is 20131111031071. The reversal of 20131111031027 is 72013011113102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20131111031027 - 214 = 20131111014643 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20131111030993 and 20131111031011.

It is not a weakly prime, because it can be changed into another prime (20131111031627) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065555515513 + 10065555515514.

It is an arithmetic number, because the mean of its divisors is an integer number (10065555515514).

Almost surely, 220131111031027 is an apocalyptic number.

20131111031027 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131111031027 is an equidigital number, since it uses as much as digits as its factorization.

20131111031027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 20131111031027 its reverse (72013011113102), we get a palindrome (92144122144129).

The spelling of 20131111031027 in words is "twenty trillion, one hundred thirty-one billion, one hundred eleven million, thirty-one thousand, twenty-seven".