Base | Representation |
---|---|
bin | 1001001001111001001000… |
… | …11101011110100011010001 |
3 | 2122021111221121022120112011 |
4 | 10210330210131132203101 |
5 | 10114312020044022231 |
6 | 110452035504102521 |
7 | 4145266001520142 |
oct | 444744435364321 |
9 | 78244847276464 |
10 | 20131123423441 |
11 | 646161a39a898 |
12 | 2311668604a41 |
13 | b30483b4a964 |
14 | 4d84cca01ac9 |
15 | 24d9cb65a9b1 |
hex | 124f2475e8d1 |
20131123423441 has 2 divisors, whose sum is σ = 20131123423442. Its totient is φ = 20131123423440.
The previous prime is 20131123423343. The next prime is 20131123423471. The reversal of 20131123423441 is 14432432113102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12206498688400 + 7924624735041 = 3493780^2 + 2815071^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20131123423441 is a prime.
It is not a weakly prime, because it can be changed into another prime (20131123423471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065561711720 + 10065561711721.
It is an arithmetic number, because the mean of its divisors is an integer number (10065561711721).
Almost surely, 220131123423441 is an apocalyptic number.
It is an amenable number.
20131123423441 is a deficient number, since it is larger than the sum of its proper divisors (1).
20131123423441 is an equidigital number, since it uses as much as digits as its factorization.
20131123423441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 20131123423441 its reverse (14432432113102), we get a palindrome (34563555536543).
The spelling of 20131123423441 in words is "twenty trillion, one hundred thirty-one billion, one hundred twenty-three million, four hundred twenty-three thousand, four hundred forty-one".
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