Base | Representation |
---|---|
bin | 11101010010110110111… |
… | …000101010010110100001 |
3 | 21010110012022021100011202 |
4 | 131102312320222112201 |
5 | 230440323412021002 |
6 | 4140451130050545 |
7 | 265304550114542 |
oct | 35226670522641 |
9 | 7113168240152 |
10 | 2013113001377 |
11 | 706835897905 |
12 | 2861a3579a55 |
13 | 117ab317c59a |
14 | 6d6142324c9 |
15 | 37574301502 |
hex | 1d4b6e2a5a1 |
2013113001377 has 2 divisors, whose sum is σ = 2013113001378. Its totient is φ = 2013113001376.
The previous prime is 2013113001343. The next prime is 2013113001439. The reversal of 2013113001377 is 7731003113102.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1920009294736 + 93103706641 = 1385644^2 + 305129^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013113001377 - 212 = 2013112997281 is a prime.
It is a super-2 number, since 2×20131130013772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2013113021377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006556500688 + 1006556500689.
It is an arithmetic number, because the mean of its divisors is an integer number (1006556500689).
Almost surely, 22013113001377 is an apocalyptic number.
It is an amenable number.
2013113001377 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013113001377 is an equidigital number, since it uses as much as digits as its factorization.
2013113001377 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2646, while the sum is 29.
Adding to 2013113001377 its reverse (7731003113102), we get a palindrome (9744116114479).
The spelling of 2013113001377 in words is "two trillion, thirteen billion, one hundred thirteen million, one thousand, three hundred seventy-seven".
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