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20131133033 = 111830103003
BaseRepresentation
bin10010101111111010…
…001011011001101001
31220221222021111221202
4102233322023121221
5312212032224113
613125332013545
71311603543644
oct225772133151
956858244852
1020131133033
1185a0555230
123a99a612b5
131b8a8cc04b
14d8d89ca5b
157cc520258
hex4afe8b669

20131133033 has 4 divisors (see below), whose sum is σ = 21961236048. Its totient is φ = 18301030020.

The previous prime is 20131133021. The next prime is 20131133039. The reversal of 20131133033 is 33033113102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20131133033 - 210 = 20131132009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20131132996 and 20131133014.

It is not an unprimeable number, because it can be changed into a prime (20131133039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915051491 + ... + 915051512.

It is an arithmetic number, because the mean of its divisors is an integer number (5490309012).

Almost surely, 220131133033 is an apocalyptic number.

It is an amenable number.

20131133033 is a deficient number, since it is larger than the sum of its proper divisors (1830103015).

20131133033 is a wasteful number, since it uses less digits than its factorization.

20131133033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1830103014.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 20131133033 its reverse (33033113102), we get a palindrome (53164246135).

The spelling of 20131133033 in words is "twenty billion, one hundred thirty-one million, one hundred thirty-three thousand, thirty-three".

Divisors: 1 11 1830103003 20131133033