201312011431 has 2 divisors, whose sum is σ = 201312011432. Its totient is φ = 201312011430.

The previous prime is 201312011393. The next prime is 201312011441. The reversal of 201312011431 is 134110213102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201312011431 - 2¹⁵ = 201311978663 is a prime.

It is a super-2 number, since 2×201312011431² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201312011399 and 201312011408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201312011441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656005715 + 100656005716.

It is an arithmetic number, because the mean of its divisors is an integer number (100656005716).

Almost surely, 2^201312011431 is an apocalyptic number.

201312011431 is a deficient number, since it is larger than the sum of its proper divisors (1).

201312011431 is an equidigital number, since it uses as much as digits as its factorization.

201312011431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 201312011431 its reverse (134110213102), we get a palindrome (335422224533).

The spelling of 201312011431 in words is "two hundred one billion, three hundred twelve million, eleven thousand, four hundred thirty-one".