2013120223 has 2 divisors, whose sum is σ = 2013120224. Its totient is φ = 2013120222.

The previous prime is 2013120203. The next prime is 2013120227. The reversal of 2013120223 is 3220213102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2013120223 is a prime.

It is a super-3 number, since 3×2013120223³ (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013120197 and 2013120206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013120227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006560111 + 1006560112.

It is an arithmetic number, because the mean of its divisors is an integer number (1006560112).

Almost surely, 2^2013120223 is an apocalyptic number.

2013120223 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013120223 is an equidigital number, since it uses as much as digits as its factorization.

2013120223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 2013120223 is about 44867.8083150938. The cubic root of 2013120223 is about 1262.6701214140.

Adding to 2013120223 its reverse (3220213102), we get a palindrome (5233333325).

The spelling of 2013120223 in words is "two billion, thirteen million, one hundred twenty thousand, two hundred twenty-three".