Base | Representation |
---|---|
bin | 1011101101111100100… |
… | …0011011001110010001 |
3 | 201020121210002101022012 |
4 | 2323133020123032101 |
5 | 11244241334222231 |
6 | 232251555152305 |
7 | 20354461652144 |
oct | 2733710331621 |
9 | 636553071265 |
10 | 201312023441 |
11 | 784154308a1 |
12 | 33022ba5695 |
13 | 15ca30a69c9 |
14 | 9a5a45205b |
15 | 538373be2b |
hex | 2edf21b391 |
201312023441 has 4 divisors (see below), whose sum is σ = 201394632372. Its totient is φ = 201229414512.
The previous prime is 201312023413. The next prime is 201312023453. The reversal of 201312023441 is 144320213102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 183523132816 + 17788890625 = 428396^2 + 133375^2 .
It is a cyclic number.
It is not a de Polignac number, because 201312023441 - 234 = 184132154257 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (201312023641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41300810 + ... + 41305683.
It is an arithmetic number, because the mean of its divisors is an integer number (50348658093).
Almost surely, 2201312023441 is an apocalyptic number.
It is an amenable number.
201312023441 is a deficient number, since it is larger than the sum of its proper divisors (82608931).
201312023441 is an equidigital number, since it uses as much as digits as its factorization.
201312023441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82608930.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 201312023441 its reverse (144320213102), we get a palindrome (345632236543).
The spelling of 201312023441 in words is "two hundred one billion, three hundred twelve million, twenty-three thousand, four hundred forty-one".
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