201312034211041 has 4 divisors (see below), whose sum is σ = 216797575304212. Its totient is φ = 185826493117872.

The previous prime is 201312034211021. The next prime is 201312034211087. The reversal of 201312034211041 is 140112430213102.

201312034211041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 88283688483600 + 113028345727441 = 9395940^2 + 10631479^2 .

It is a cyclic number.

It is not a de Polignac number, because 201312034211041 - 2¹³ = 201312034202849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201312034210997 and 201312034211015.

It is not an unprimeable number, because it can be changed into a prime (201312034211021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7742770546566 + ... + 7742770546591.

It is an arithmetic number, because the mean of its divisors is an integer number (54199393826053).

Almost surely, 2^{201312034211041} is an apocalyptic number.

It is an amenable number.

201312034211041 is a deficient number, since it is larger than the sum of its proper divisors (15485541093171).

201312034211041 is a wasteful number, since it uses less digits than its factorization.

201312034211041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15485541093170.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 201312034211041 its reverse (140112430213102), we get a palindrome (341424464424143).

The spelling of 201312034211041 in words is "two hundred one trillion, three hundred twelve billion, thirty-four million, two hundred eleven thousand, forty-one".