Base | Representation |
---|---|
bin | 111011111111101… |
… | …1100101101111011 |
3 | 12012022001011101222 |
4 | 1313333130231323 |
5 | 13110324341103 |
6 | 531432102255 |
7 | 100613151416 |
oct | 16777345573 |
9 | 5168034358 |
10 | 2013121403 |
11 | 9433999a7 |
12 | 48223498b |
13 | 2610bc8c7 |
14 | 151512b7d |
15 | bbb05638 |
hex | 77fdcb7b |
2013121403 has 2 divisors, whose sum is σ = 2013121404. Its totient is φ = 2013121402.
The previous prime is 2013121399. The next prime is 2013121417. The reversal of 2013121403 is 3041213102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013121403 - 22 = 2013121399 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (2013129403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006560701 + 1006560702.
It is an arithmetic number, because the mean of its divisors is an integer number (1006560702).
Almost surely, 22013121403 is an apocalyptic number.
2013121403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013121403 is an equidigital number, since it uses as much as digits as its factorization.
2013121403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 2013121403 is about 44867.8214648316. The cubic root of 2013121403 is about 1262.6703681206.
Adding to 2013121403 its reverse (3041213102), we get a palindrome (5054334505).
The spelling of 2013121403 in words is "two billion, thirteen million, one hundred twenty-one thousand, four hundred three".
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