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2013121403 is a prime number
BaseRepresentation
bin111011111111101…
…1100101101111011
312012022001011101222
41313333130231323
513110324341103
6531432102255
7100613151416
oct16777345573
95168034358
102013121403
119433999a7
1248223498b
132610bc8c7
14151512b7d
15bbb05638
hex77fdcb7b

2013121403 has 2 divisors, whose sum is σ = 2013121404. Its totient is φ = 2013121402.

The previous prime is 2013121399. The next prime is 2013121417. The reversal of 2013121403 is 3041213102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013121403 - 22 = 2013121399 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (2013129403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006560701 + 1006560702.

It is an arithmetic number, because the mean of its divisors is an integer number (1006560702).

Almost surely, 22013121403 is an apocalyptic number.

2013121403 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013121403 is an equidigital number, since it uses as much as digits as its factorization.

2013121403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2013121403 is about 44867.8214648316. The cubic root of 2013121403 is about 1262.6703681206.

Adding to 2013121403 its reverse (3041213102), we get a palindrome (5054334505).

The spelling of 2013121403 in words is "two billion, thirteen million, one hundred twenty-one thousand, four hundred three".