Base | Representation |
---|---|
bin | 101101110001011110100110… |
… | …010011010100011011100011 |
3 | 222101210020222111121011100202 |
4 | 231301132212103110123203 |
5 | 202341244342231304331 |
6 | 1552053314324535415 |
7 | 60255220016145404 |
oct | 5561364623243343 |
9 | 871706874534322 |
10 | 201312202213091 |
11 | 59165030a50872 |
12 | 1a6b37a125156b |
13 | 884387539b548 |
14 | 379d7c39c79ab |
15 | 18418d4379ecb |
hex | b717a64d46e3 |
201312202213091 has 2 divisors, whose sum is σ = 201312202213092. Its totient is φ = 201312202213090.
The previous prime is 201312202213061. The next prime is 201312202213121. The reversal of 201312202213091 is 190312202213102.
It is a balanced prime because it is at equal distance from previous prime (201312202213061) and next prime (201312202213121).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201312202213091 is a prime.
It is not a weakly prime, because it can be changed into another prime (201312202213061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656101106545 + 100656101106546.
It is an arithmetic number, because the mean of its divisors is an integer number (100656101106546).
Almost surely, 2201312202213091 is an apocalyptic number.
201312202213091 is a deficient number, since it is larger than the sum of its proper divisors (1).
201312202213091 is an equidigital number, since it uses as much as digits as its factorization.
201312202213091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 201312202213091 its reverse (190312202213102), we get a palindrome (391624404426193).
The spelling of 201312202213091 in words is "two hundred one trillion, three hundred twelve billion, two hundred two million, two hundred thirteen thousand, ninety-one".
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