Base | Representation |
---|---|
bin | 11101010010110111011… |
… | …110111011100011010101 |
3 | 21010110020000011000101111 |
4 | 131102313132323203111 |
5 | 230440333444031201 |
6 | 4140452125055021 |
7 | 265305031306252 |
oct | 35226736734325 |
9 | 7113200130344 |
10 | 2013123033301 |
11 | 706840519a56 |
12 | 2861a69b7471 |
13 | 117ab5282833 |
14 | 6d6156c4429 |
15 | 37575133b51 |
hex | 1d4b77bb8d5 |
2013123033301 has 4 divisors (see below), whose sum is σ = 2017223080704. Its totient is φ = 2009022985900.
The previous prime is 2013123033289. The next prime is 2013123033323. The reversal of 2013123033301 is 1033303213102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013123033301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013123033391) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050022965 + ... + 2050023946.
It is an arithmetic number, because the mean of its divisors is an integer number (504305770176).
Almost surely, 22013123033301 is an apocalyptic number.
It is an amenable number.
2013123033301 is a deficient number, since it is larger than the sum of its proper divisors (4100047403).
2013123033301 is an equidigital number, since it uses as much as digits as its factorization.
2013123033301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4100047402.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 2013123033301 its reverse (1033303213102), we get a palindrome (3046426246403).
The spelling of 2013123033301 in words is "two trillion, thirteen billion, one hundred twenty-three million, thirty-three thousand, three hundred one".
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