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2013123033301 = 4914100046911
BaseRepresentation
bin11101010010110111011…
…110111011100011010101
321010110020000011000101111
4131102313132323203111
5230440333444031201
64140452125055021
7265305031306252
oct35226736734325
97113200130344
102013123033301
11706840519a56
122861a69b7471
13117ab5282833
146d6156c4429
1537575133b51
hex1d4b77bb8d5

2013123033301 has 4 divisors (see below), whose sum is σ = 2017223080704. Its totient is φ = 2009022985900.

The previous prime is 2013123033289. The next prime is 2013123033323. The reversal of 2013123033301 is 1033303213102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013123033301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013123033391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050022965 + ... + 2050023946.

It is an arithmetic number, because the mean of its divisors is an integer number (504305770176).

Almost surely, 22013123033301 is an apocalyptic number.

It is an amenable number.

2013123033301 is a deficient number, since it is larger than the sum of its proper divisors (4100047403).

2013123033301 is an equidigital number, since it uses as much as digits as its factorization.

2013123033301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4100047402.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2013123033301 its reverse (1033303213102), we get a palindrome (3046426246403).

The spelling of 2013123033301 in words is "two trillion, thirteen billion, one hundred twenty-three million, thirty-three thousand, three hundred one".

Divisors: 1 491 4100046911 2013123033301