Base | Representation |
---|---|
bin | 11101010010110111011… |
… | …111001011111000111111 |
3 | 21010110020000021102012002 |
4 | 131102313133023320333 |
5 | 230440334003201343 |
6 | 4140452130332515 |
7 | 265305032005334 |
oct | 35226737137077 |
9 | 7113200242162 |
10 | 2013123100223 |
11 | 706840565264 |
12 | 2861a6a2a13b |
13 | 117ab52a7131 |
14 | 6d61570098b |
15 | 375751488b8 |
hex | 1d4b77cbe3f |
2013123100223 has 2 divisors, whose sum is σ = 2013123100224. Its totient is φ = 2013123100222.
The previous prime is 2013123100217. The next prime is 2013123100259. The reversal of 2013123100223 is 3220013213102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013123100223 - 216 = 2013123034687 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2013123100195 and 2013123100204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013123100523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006561550111 + 1006561550112.
It is an arithmetic number, because the mean of its divisors is an integer number (1006561550112).
Almost surely, 22013123100223 is an apocalyptic number.
2013123100223 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013123100223 is an equidigital number, since it uses as much as digits as its factorization.
2013123100223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2013123100223 its reverse (3220013213102), we get a palindrome (5233136313325).
The spelling of 2013123100223 in words is "two trillion, thirteen billion, one hundred twenty-three million, one hundred thousand, two hundred twenty-three".
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