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2013123440142 = 232111840191119
BaseRepresentation
bin11101010010110111100…
…000011110111000001110
321010110020000220200110200
4131102313200132320032
5230440334100041032
64140452141514330
7265305034622343
oct35226740367016
97113200820420
102013123440142
11706840777691
122861a6b729a6
13117ab5395a79
146d61578c7ca
15375751b447c
hex1d4b781ee0e

2013123440142 has 12 divisors (see below), whose sum is σ = 4361767453680. Its totient is φ = 671041146708.

The previous prime is 2013123440129. The next prime is 2013123440177. The reversal of 2013123440142 is 2410443213102.

2013123440142 is a `hidden beast` number, since 2 + 0 + 1 + 312 + 344 + 0 + 1 + 4 + 2 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55920095542 + ... + 55920095577.

It is an arithmetic number, because the mean of its divisors is an integer number (363480621140).

Almost surely, 22013123440142 is an apocalyptic number.

2013123440142 is an abundant number, since it is smaller than the sum of its proper divisors (2348644013538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013123440142 is a wasteful number, since it uses less digits than its factorization.

2013123440142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111840191127 (or 111840191124 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 2013123440142 its reverse (2410443213102), we get a palindrome (4423566653244).

The spelling of 2013123440142 in words is "two trillion, thirteen billion, one hundred twenty-three million, four hundred forty thousand, one hundred forty-two".

Divisors: 1 2 3 6 9 18 111840191119 223680382238 335520573357 671041146714 1006561720071 2013123440142