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20131300117 is a prime number
BaseRepresentation
bin10010101111111010…
…110100001100010101
31220221222121000011001
4102233322310030111
5312212103100432
613125335343301
71311605141035
oct225772641425
956858530131
1020131300117
1185a0659815
123a99b21b31
131b8a95a106
14d8d9038c5
157cc5549e7
hex4afeb4315

20131300117 has 2 divisors, whose sum is σ = 20131300118. Its totient is φ = 20131300116.

The previous prime is 20131300061. The next prime is 20131300121. The reversal of 20131300117 is 71100313102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17378094276 + 2753205841 = 131826^2 + 52471^2 .

It is a cyclic number.

It is not a de Polignac number, because 20131300117 - 227 = 19997082389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20131300094 and 20131300103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20131300517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10065650058 + 10065650059.

It is an arithmetic number, because the mean of its divisors is an integer number (10065650059).

Almost surely, 220131300117 is an apocalyptic number.

It is an amenable number.

20131300117 is a deficient number, since it is larger than the sum of its proper divisors (1).

20131300117 is an equidigital number, since it uses as much as digits as its factorization.

20131300117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 20131300117 its reverse (71100313102), we get a palindrome (91231613219).

The spelling of 20131300117 in words is "twenty billion, one hundred thirty-one million, three hundred thousand, one hundred seventeen".