Base | Representation |
---|---|
bin | 11101010010110111111… |
… | …101011100010111110011 |
3 | 21010110020120012101121111 |
4 | 131102313331130113303 |
5 | 230440343021011201 |
6 | 4140453012334151 |
7 | 265305156302236 |
oct | 35226775342763 |
9 | 7113216171544 |
10 | 2013131032051 |
11 | 706844a92597 |
12 | 2861a9614357 |
13 | 117ab6b23519 |
14 | 6d6167a741d |
15 | 37575bb3b51 |
hex | 1d4b7f5c5f3 |
2013131032051 has 2 divisors, whose sum is σ = 2013131032052. Its totient is φ = 2013131032050.
The previous prime is 2013131032049. The next prime is 2013131032057. The reversal of 2013131032051 is 1502301313102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013131032051 - 21 = 2013131032049 is a prime.
Together with 2013131032049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2013131032057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006565516025 + 1006565516026.
It is an arithmetic number, because the mean of its divisors is an integer number (1006565516026).
Almost surely, 22013131032051 is an apocalyptic number.
2013131032051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013131032051 is an equidigital number, since it uses as much as digits as its factorization.
2013131032051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 2013131032051 its reverse (1502301313102), we get a palindrome (3515432345153).
The spelling of 2013131032051 in words is "two trillion, thirteen billion, one hundred thirty-one million, thirty-two thousand, fifty-one".
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