201313111231 has 2 divisors, whose sum is σ = 201313111232. Its totient is φ = 201313111230.

The previous prime is 201313111213. The next prime is 201313111253. The reversal of 201313111231 is 132111313102.

Together with previous prime (201313111213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-201313111231 is a prime.

It is a super-2 number, since 2×201313111231² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201313111199 and 201313111208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201313111211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656555615 + 100656555616.

It is an arithmetic number, because the mean of its divisors is an integer number (100656555616).

Almost surely, 2^201313111231 is an apocalyptic number.

201313111231 is a deficient number, since it is larger than the sum of its proper divisors (1).

201313111231 is an equidigital number, since it uses as much as digits as its factorization.

201313111231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 201313111231 its reverse (132111313102), we get a palindrome (333424424333).

The spelling of 201313111231 in words is "two hundred one billion, three hundred thirteen million, one hundred eleven thousand, two hundred thirty-one".