Base | Representation |
---|---|
bin | 11101010010110111111… |
… | …110000111110100011011 |
3 | 21010110020120112102201121 |
4 | 131102313332013310123 |
5 | 230440343042210021 |
6 | 4140453020230111 |
7 | 265305160643125 |
oct | 35226776076433 |
9 | 7113216472647 |
10 | 2013131210011 |
11 | 7068450a4269 |
12 | 2861a969b337 |
13 | 117ab6b8651c |
14 | 6d616812215 |
15 | 37575beb741 |
hex | 1d4b7f87d1b |
2013131210011 has 4 divisors (see below), whose sum is σ = 2013213770224. Its totient is φ = 2013048649800.
The previous prime is 2013131209961. The next prime is 2013131210017. The reversal of 2013131210011 is 1100121313102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013131210011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013131210017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41243520 + ... + 41292301.
It is an arithmetic number, because the mean of its divisors is an integer number (503303442556).
Almost surely, 22013131210011 is an apocalyptic number.
2013131210011 is a deficient number, since it is larger than the sum of its proper divisors (82560213).
2013131210011 is an equidigital number, since it uses as much as digits as its factorization.
2013131210011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82560212.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 2013131210011 its reverse (1100121313102), we get a palindrome (3113252523113).
The spelling of 2013131210011 in words is "two trillion, thirteen billion, one hundred thirty-one million, two hundred ten thousand, eleven".
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