Base | Representation |
---|---|
bin | 1011101101111100110… |
… | …1011010101110110111 |
3 | 201020121212112212111221 |
4 | 2323133031122232313 |
5 | 11244242203112101 |
6 | 232252043211211 |
7 | 20354506042501 |
oct | 2733715325667 |
9 | 636555485457 |
10 | 201313332151 |
11 | 78416145078 |
12 | 33023516b07 |
13 | 15ca34445a9 |
14 | 9a5a6b2d71 |
15 | 53838e9aa1 |
hex | 2edf35abb7 |
201313332151 has 2 divisors, whose sum is σ = 201313332152. Its totient is φ = 201313332150.
The previous prime is 201313332049. The next prime is 201313332211. The reversal of 201313332151 is 151233313102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201313332151 - 235 = 166953593783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201313332251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100656666075 + 100656666076.
It is an arithmetic number, because the mean of its divisors is an integer number (100656666076).
Almost surely, 2201313332151 is an apocalyptic number.
201313332151 is a deficient number, since it is larger than the sum of its proper divisors (1).
201313332151 is an equidigital number, since it uses as much as digits as its factorization.
201313332151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 201313332151 its reverse (151233313102), we get a palindrome (352546645253).
The spelling of 201313332151 in words is "two hundred one billion, three hundred thirteen million, three hundred thirty-two thousand, one hundred fifty-one".
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